If it's not what You are looking for type in the equation solver your own equation and let us solve it.
z^2+256=0
a = 1; b = 0; c = +256;
Δ = b2-4ac
Δ = 02-4·1·256
Δ = -1024
Delta is less than zero, so there is no solution for the equation
| X-5÷x-3=3/5 | | 3x(x-4)=9x | | 3x-1=2x+1=3x+1=x+5=4x-3=4x-5 | | 2+3x+1=6x+1 | | (x+7)+(x-10)=39 | | 8x+13=67 | | y+y+6=12 | | -k/8=4 | | (4y^2-5y+2)=(6y^2-5) | | X²+2x+1=25 | | 1.6=y+1.5 | | 8x+3=16x–1 | | 6x-4+10=12 | | n+81=9n−7 | | h+(-8)=-2 | | 5(1-3x)=20 | | (-3k)+23=(-2k)+17 | | 2t+6/5=4+-6 | | 4a+6=(-7a)-5 | | 0,19x=0,15 | | 3(x-2)=(-4)(x+5) | | 3(4-x)=10(x+5) | | 2(x+7)=(-x)-25 | | 600a+2400×180=40 | | 6.253*5.07=x | | 8x-9=7x-5 | | 3x-10=105=2x+70 | | (6x-5)/2x=7/9 | | x=15+2/3 | | 2x-10=37-x=5x-5=65=34=25 | | 5-6m=29 | | 3x-3=x+5=2x-7=4x-8=6x-27=3x-5 |